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# ft\_ultimate\_ft

**Objective:**

Create a function that takes a **pointer to a pointer to a pointer** (repeated 9 times) to an integer and sets the value of the integer to `42`.

**Turn-in Requirements:**

* **Directory**: `ex01/`
* **File**: `ft_ultimate_ft.c`
* **Allowed Functions**: None

**Prototype:**

```c
void ft_ultimate_ft(int *********nbr);
```

**Implementation:**

Here’s how you can implement the function:

```c
// File: ft_ultimate_ft.c
#include <unistd.h> // Optional, not needed for this task but can be standard practice for headers

void ft_ultimate_ft(int *********nbr)
{
    *********nbr = 42; // Set the value of the integer to 42 through the multi-level pointer
}
```

**Explanation:**

1. **Multi-level Pointers**:
   * The function accepts a 9-level deep pointer: `*********nbr`.
   * Each `*` dereferences one level of pointer to eventually access the integer.
2. **Assignment**:
   * The final dereference `*********nbr` accesses the value at the deepest memory location.
   * Assigning `42` to it sets the integer to `42`.

**Example Usage:**

```c
#include <stdio.h>

void ft_ultimate_ft(int *********nbr);

int main()
{
    int value = 0;
    int *p1 = &value;
    int **p2 = &p1;
    int ***p3 = &p2;
    int ****p4 = &p3;
    int *****p5 = &p4;
    int ******p6 = &p5;
    int *******p7 = &p6;
    int ********p8 = &p7;
    int *********p9 = &p8;

    ft_ultimate_ft(p9); // Pass the 9-level deep pointer
    printf("The value is: %d\n", value); // Should print: The value is: 42

    return 0;
}
```

**Notes:**

* Ensure your code complies with **Norminette** standards.
* Be careful with pointer initialization in the example; missing one level will result in a segmentation fault.


---

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